Two points separated by a distance of 0.1 mm can just be resolved by a microscope when light of wavelength $6000 \circ A$ is used. If light of wavelength 4800 Å is used, this limit of resolution becomes

0.08 mm

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0.10 mm

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0.12 mm

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0.06 mm

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Solution

The correct option is A 0.08 mm
By using resolving limit (R.L.) $\propto λ \Rightarrow \frac{(R . L)_{1}}{(R . L)_{2}} = \frac{λ_{1}}{λ_{2}} \Rightarrow \frac{0.1}{(R . L)_{2}} = \frac{6000}{4800} \Rightarrow (R . L)_{2} = 0.08 m m .$

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Two points separated by a distance of 0.1 mm can just be resolved by a microscope when light of wavelength 6000∘A is used. If light of wavelength 4800 Å is used, this limit of resolution becomes

The correct option is A 0.08 mm By using resolving limit (R.L.) ∝λ⇒(R.L)1(R.L)2=λ1λ2⇒0.1(R.L)2=60004800⇒(R.L)2=0.08mm.

Two points separated by a distance of 0.1 mm can just be resolved by a microscope when light of wavelength $6000 \circ A$ is used. If light of wavelength 4800 Å is used, this limit of resolution becomes

The correct option is A 0.08 mm
By using resolving limit (R.L.) $\propto λ \Rightarrow \frac{(R . L)_{1}}{(R . L)_{2}} = \frac{λ_{1}}{λ_{2}} \Rightarrow \frac{0.1}{(R . L)_{2}} = \frac{6000}{4800} \Rightarrow (R . L)_{2} = 0.08 m m .$