Question

Two points separated by a distance of 0.1 mm can just be seen with a microscope with a light of wavelength 6000 $\stackrel{{}^{\circ }}{A}$. If the light of wavelength 4800 $\stackrel{{}^{\circ }}{A}$ is used, the limit of resolution will be

• A. 7 cm
• B. 9 cm
• C. 0.08 mm
• D. 8 mm

Answer 1

The correct option is C 0.08 mm

As limit of resolution $\alpha$ wavelength
$\therefore$ New limit of resolution = $\left(\frac{newwavelength}{previouswavelength}\right)$ (previous limit of resolution)
= $\left(\frac{4800}{6000}\right)\left(0.1mm\right)$
= $0.08mm$