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Question

Two positive ions, each carrying a charge q, are separated by a distance d, repulsion between the ions, the number of electrons missing from each ion will be:

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Solution

According to Coulomb's law,
F=14πϵ0(q)(q)d2F=q24πϵ0d2q2=4πϵ0Fd2q=4πϵ0Fd2Sinceq=nen=qen=4πϵ0Fd2e=4πϵ0Fd2e2

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