Two positive ions, each carrying a charge q, are separated by a distance d, repulsion between the ions, the number of electrons missing from each ion will be:
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Solution
According to Coulomb's law, F=14πϵ0(q)(q)d2⇒F=q24πϵ0d2q2=4πϵ0Fd2⇒q=√4πϵ0Fd2Sinceq=ne∴n=qe⇒n=√4πϵ0Fd2e=√4πϵ0Fd2e2