Question

Two protons are kept at a separation of $40A^o$. $F_n$ is the nuclear force and $F_e$ is the electrostatic force between them. Then

• A. $F_n\gg F_e$
• B. $F_n=F_e$
• C. $F_n\ll F_e$
• D. $F_n\approx F_e$

Answer 1

Answer: (A)

$F_n\gg F_e$

Nuclear forces are attractive in nature:- The magnitude which depends upon inter nucleon distance is of very high order.

Since inside the nucleus they are bound to stay there so attraction of $F_n$ is higher than the repulsion of $F_e$