Two reactions, A→products and B→products, have rate constant Ka and Kb at temperature T and activation energies Ea and Eb respectively. If Ka>Kb and Ea>Eb and assuming that A for both the reactions is same then:
A
at higher temperature Ka will be greater than Kb
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B
at lower temperature Ka and Kb will differ more and Ka>Kb
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C
as temperature rises Ka and Kb will be close to each other in magnitude
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D
all of the above
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Solution
The correct option is D all of the above As we know, Ka=Ae−Ea/RT and Kb=Ae−Eb/RT Also given, Ka>Kb Ea<Eb So, at higher temperature Ka will be greater than Kb. Also, at lower temperature Ka and Kb will differ more and Ka>Kb.