Two resistance wires on joining in parallel- the resultant resistance is 6 - - One of the wire breaks- The effective resistance is 2 - - The resistance of the broken wire was

The correct option is D 3 Ω1/R_1+1/R_2=1/R_eqv 1/2+1/R_2=1/6 R_2 =3 Ω ...

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Standard X

Physics

Resistors in parallel

Two resistanc...

Question

Two resistance wires on joining in parallel, the resultant resistance is 6 Ω. One of the wire breaks. The effective resistance is 2 Ω. The resistance of the broken wire was

5Ω

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6Ω

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2 Ω

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3 Ω

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Solution

The correct option is D
3 Ω

$\frac{1}{R_{1}} + \frac{1}{R_{2}} = \frac{1}{R_{e q v}} \frac{1}{2} + \frac{1}{R_{2}} = \frac{1}{6} R_{2} = 3 Ω$

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Two resistance wires on joining in parallel, the resultant resistance is 6 Ω. One of the wire breaks. The effective resistance is 2 Ω. The resistance of the broken wire was

The correct option is D 3 Ω1R1+1R2=1Reqv12+1R2=16R2=3Ω

The correct option is D
3 Ω

$\frac{1}{R_{1}} + \frac{1}{R_{2}} = \frac{1}{R_{e q v}} \frac{1}{2} + \frac{1}{R_{2}} = \frac{1}{6} R_{2} = 3 Ω$