Two resistances R1 and R2 give an equivalent resistance of 4.5 Ω when connected in series and 1 Ω when connected in parallel. Then the value of resistances are___________.
1.5 , 3
For series combination, Req= R1 + R2
4.5 = R1 + R2 (Given) ......... (i)
For parallel combination, Req=R1R2R1+R2
1 = R1R24.5
or, R1R2=4.5
R1= 4.5R2 ......... (ii)
Put the value of R1 in eqn. (i).
Substituting and solving we get,
R1= 1.5 Ω, R2= 3 Ω