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Question

Two resistances R1 and R2 provide series to parallel equivalents as n1. Then the correct relationship is

A
(R1R2)2+(R2R1)2=n2
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B
(R1R2)3/2+(R2R1)3/2=n3/2
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C
(R1R2)+(R2R1)=n
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D
(R1R2)1/2+(R2R1)1/2=n1/2
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Solution

The correct option is D (R1R2)1/2+(R2R1)1/2=n1/2
Series resistance RS=R1+R2 and parallel resistance RP=R1R2R1+R2RSRP=(R1+R2)2R1R2=n
R1+R2R1R2=nR21R1R2+R22R1R2=nR1R2+R2R1=n

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