Two resistors of 2 ohm and 4 ohm are connected in a parallel circuit. If the magnitude of current in the 2 ohm is I, the magnitude of current in the 4 ohm resistor is:
In a parallel circuit the potential differences are same in both the resistors
Voltage Drop=Current×Resistance
Let the current be I2
⇒I×2=I2×4
I2=I2
So the current through 4Ω resistor is I2