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Question

Two resistors of 2 ohm and 4 ohm are connected in a parallel circuit. If the magnitude of current in the 2 ohm is I, the magnitude of current in the 4 ohm resistor is:

A
I
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B
I/2
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C
2/I
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D
I/4
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Solution

The correct option is A I/2

In a parallel circuit the potential differences are same in both the resistors

Voltage Drop=Current×Resistance

Let the current be I2

I×2=I2×4

I2=I2

So the current through 4Ω resistor is I2



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