Question

Two resistors of resistances $2\Omega$ and $6\Omega$ are connected in parallel. This combination is then connected to a battery of emf 2V and internal resistance $0.5\Omega$. What is the current flowing through the battery?

• A. 4 A
• B. $\frac{4}{3}A$
• C. $\frac{4}{17}A$
• D. 1 A

Answer 1

The correct option is D 1 A

Equivalent resistance of the circuit $R_{eq}=(2\parallel 6)+0.5$ $\Omega$

$\therefore$ $R_{eq}=\frac{2\times 6}{2+6}+0.5=1.5+0.5=2\Omega$

Current flowing in the circuit $I=\frac{V}{R_{eq}}$

$⟹$ $I=\frac{2}{2}=1A$