Question

Two resistors of resistances $5\Omega and12\Omega$ are connected in series. The equivalent resistance is:

• A. $13\Omega$
• B. $\frac{60}{17}\Omega$
• C. $17\Omega$
• D. $7\Omega$

Answer 1

The correct option is C $17\Omega$

When resistors are connected in series, the equivalent resistance is the sum of the individual resistances.
Hence, $R_{eq}=R_1+R_2$
$=5\Omega +12\Omega =17\Omega$