wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two rigid bodies A and B rotate with angular momenta LA and LB respectively. The moments of inertia of A and B about the axes of rotation are IA and IB respectively. If IA=IB/4 and LA=5LB. Then the ratio of rotational kinetic energy KA of A to the rotational energy KB of B is given by

A
KAKB=254
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
KAKB=54
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
KAKB=14
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
KAKB=100
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D KAKB=100
Rotational K.E, K=12Iw2
Also, L=IwK=L22I
KAKB=L2AL2BIBIA
KAKB=25L2BL2B4IAIA
KAKB=100


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rotational Kinematics
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon