Two roads cross at right angles at O. One person A walking along one of the roads at 3ms−1 sees another person B walking at 4ms−1 along the other road at O, when he is 10m off. The nearest distance between the two persons is
A
10m
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B
9m
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C
8m
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D
7.2m
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Solution
The correct option is C8m x2=(10−3t)2+4t2 x=[(5t−6)2+64]12