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Question

Two schools A and B want to award their selected students on the values of sincerity, truthfulness and helpfulness. The school A wants to award Rs.x each, Rs.y each and Rs.z each for the three respective values to its 3, 2 and 1 students with a total award money of Rs.1600. School B wants to spend Rs.2300 to award its 4, 1 and 3 students on the respective values (by giving the same award money for the three values as before). If the total amount of awards for one prize on each value is Rs.900, using matrices, find the award money for each value.

Apart from these three values, suggest one more value which should be considered for award.

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Solution

Let the award money spent on the values of sincerity, truthfifiness and helpfulness he Rs.x each. Rs.y each and Rs.z each respectively.

3x+2y+z=1600,4x+y+3z=2300,x+y+z=900

The given situation can be expressed as: 321413111xyz=16002300900

where A=321413111,x=xyz,B=16002300900 AX=B X=A1B (i)

Now, |A|=3(13)2(43)+1(41)=50, so A1 exists.


Consider Aij as the cofactors of the element aij of matrix A.

A11=2, A12=1, A13==3A21=1,A22=2, A23=1A31=5, A32=5,A33=5

So, adj.A=215125315 A1=1|A|adj.A=15215125315

By (i), X=151|A|adj.A=1521512531516002300900 xyz200300400

By equality of matrices, we get : x = 200, y = 300, z = 400 .

Hence the award money for the values of sincerity, tnithfulness and helpfulness is Rs.200, Rs.300 and Rs.400 respectively.

Also, the value of Obedience can be included for the awards.


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