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Question

Two schools P and Q want to award their selected students on the values of Discipline, Politeness and Punctuality. The school P wants to award ₹x each, ₹y each and ₹z each the three respectively values to its 3, 2 and 1 students with a total award money of ₹1,000. School Q wants to spend ₹1,500 to award its 4, 1 and 3 students on the respective values (by giving the same award money for three values as before). If the total amount of awards for one prize on each value is ₹600, using matrices, find the award money for each value. Apart from the above three values, suggest one more value for awards.

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Solution

​Let the award money given for Discipline, Politeness and Punctuality be ₹x, ₹y and ₹z respectively.

Since, the total cash award is ₹600.
∴ x + y + z = 600 ....(1)

Award money given by school P is ₹1,000.
∴ 3x + 2y + z = 1000 ....(2)

Award money given by school Q is ₹1,500.
∴ 4x + y + 3z = 1500 ....(3)

The above system of equations can be written in matrix form AX = B as
111321413xyz=60010001500Where, A=111321413, X=xyz and B=60010001500Now,A=111321413 =16-1-19-4+1(3-8) =5-5-5 =-5Let Cij be the cofactors of elements aij in A=aij. Then,C11=-11+12113=5, C12=-11+23143=-5, C13=-11+33241=-5C21=-12+11113=-2 , C22=-12+2 1143=-1 , C23=-12+31141=3C31=-13+11121=-1, C32=-13+21131=2, C33=-13+31132=-1adj A= 5-5-5-2-1 3-1 2-1T = 5-2-1-5-1 2-5 3-1A-1=1Aadj A =1-5 5-2-1-5-1 2-5 3-1X=A-1Bxyz=-15 5-2-1-5-1 2-5 3-160010001500xyz=-153000-2000-1500-3000-1000+3000-3000+3000-1500xyz=-15-500-1000-1500x=-500-5, y=-1000-5 and z=-1500-5 x= 100, y= 200 and z=300.

Hence, the award money for each value of Discipline, Politeness and Punctuality is ₹100, ₹200 and ₹300.

​One more value which should be considered for award is Honesty.

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