wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two ships are 10√2 km apart on a line joining south to north. The one further north is moving west with a speed of 25km/h while the other towards north with a speed of 25 km/h . What is their distance of closest approach and how long do they take to reach it?

Open in App
Solution

Let the first ship steaming north be named A and the other B. The relative velocity of A with respect to B is 25 √2 south west. If we extend the line along the 45° south west from the initial position of A, the distance of closest approach is the perpendicular drawn from B to this line. So, the distance of closest appraoch = 10√2 sin 45° = 10√2/√2 = 10 m Time taken to reach the distance of closest approach = distance of closest approach / relative speed = (10)/(25√2) = 0.56 h

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Distance and Displacement
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon