Let the first ship steaming north be named A and the other B. The relative velocity of A with respect to B is 25 √2 south west. If we extend the line along the 45° south west from the initial position of A, the distance of closest approach is the perpendicular drawn from B to this line. So, the distance of closest appraoch = 10√2 sin 45° = 10√2/√2 = 10 m Time taken to reach the distance of closest approach = distance of closest approach / relative speed = (10)/(25√2) = 0.56 h