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Byju's Answer
Standard XII
Physics
Newton's Law of Gravitation
Two small bod...
Question
Two small bodies of masses 10 kg and 20 kg are kept a distance 1.0 m apart and released. Assuming that only mutual gravitational forces are acting, find the speeds of the particles when the separation decreases to 0.5 m
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Solution
Δ
U
=
U
2
G
−
U
1
U
1
=
G
M
m
r
=
400
G
−
200
G
U
1
=
G
×
10
×
20
0.5
=
200
G
=
200
G
U
2
=
G
×
10
×
20
0.5
=
400
By energy conservation
1
2
m
v
2
=
U
⇒
1
2
×
20
3
×
v
2
=
200
G
v
2
=
60
G
v
=
√
60
G
v
=
6.32
×
10
−
5
m
/
s
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