Two small dipoles of dipole moment P1 and P2 are placed as shown in figure. k=14πϵo
A
Torque on P2 due to P1 is zero
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B
Torque on P1 due to P2 is 2kP1P2r3
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C
Torque on P1 due to P2 is zero
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D
Force on P1 due to P2 is zero
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Solution
The correct option is D Force on P1 due to P2 is zero
→E1 is field at →P2 due to →P1 →E2 is field at →P1 due to →P2 E1=kP1r3 and E2=2kP2r3 →τ=→P×→E
So ⇒|→τ|=P1E2sin90o=2kP1P2r3
Force F=−∂U∂r where U=−PEcosθ
here θ=π2, U = 0 and F = 0.