Two small spheres, each having a mass of 20 g, are suspended from a common point by two insultating strings of length 40 cm each. The spehres are identically charged and the separation between the balls at equilibrium is found to be 4 cm. Find the charge on each spehere.

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Solution

$T cos θ = m g T sin θ = F_{e}$
Using given conditions in above two equations, we get,
$\Rightarrow Q_{2} = 17 \times 10^{- 7} \times 10^{- 9} 17 \times 10^{- 16} Q = \sqrt{17 \times 10^{- 16}} = 4.123 \times 10^{- 8} C$

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Two small spheres, each having a mass of 20 g, are suspended from a common point by two insultating strings of length 40 cm each. The spehres are identically charged and the separation between the balls at equilibrium is found to be 4 cm. Find the charge on each spehere.

Tcosθ=mgTsinθ=Fe Using given conditions in above two equations, we get, ⇒Q2=17×10−7×10−917×10−16Q=√17×10−16=4.123×10−8C

$T cos θ = m g T sin θ = F_{e}$
Using given conditions in above two equations, we get,
$\Rightarrow Q_{2} = 17 \times 10^{- 7} \times 10^{- 9} 17 \times 10^{- 16} Q = \sqrt{17 \times 10^{- 16}} = 4.123 \times 10^{- 8} C$