Two solid compounds X and Y dissociates at a certain temperature as follows X(S)⇌A(g)+2B(g);KP1=9×10−3atm3 Y(s)⇌2B(g)+C(g);KP2=4.5×10−3atm3
The total pressure (in atm) of gases over a mixture of X and Y is :
A
0.450
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B
0.4
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C
0.45
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Solution
Let x is partial pressure of A and y is partial pressure of C when both equilibrium simultaneously established in a vessel X(s)⇌A(g)+2B(g) x(2x+2y); KP1=PA×P2B(total) Y(s)⇌C(g)+2B(g) y(2y+2x); KP2=PC×P2B(total) KP1KP2=xy⇒x=2y KP1=x(2x+2y)2 ⇒x=0.1atm; ∴y=0.05atm
Total pressure of gases =PA+PB+PC =3(x+y) =0.45atm