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Standard XII

Physics

Collision Example II

Two solid rub...

Question

Two solid rubber balls $A$ and $B$ having masses $200 & 400 gm$ respectively are moving in opposite direction with velocity of $A$ equal to $0.3 m/sec .$ After collision the two balls come to rest when the velocity of $B$ is :

0.15 m/sec

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1.5 m/sec

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- 0.15 m/sec

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None of these

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Solution

The correct option is C $- 0.15 m/sec$
$Let the velocity of 2nd ball be v m/s$
$m_{A} = 0.2 kg; v_{A} = 0.3 m/s; m_{2} = 0.4 kg; v_{2} = v$
$Applying Momentum Conservation:$
$Initial Momentum = Final Momentum$
$\Rightarrow m_{A} v_{A} + m_{B} v_{B} = 0 (final momentum) \Rightarrow 0.2 \times 0.3 + 0.4 \times v = 0 \Rightarrow - 0.06 / 0.4 = v \Rightarrow v = - 0.15 m/s$

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Two solid rubber balls A and B having masses 200 & 400 gm respectively are moving in opposite direction with velocity of A equal to 0.3 m/sec. After collision the two balls come to rest when the velocity of B is :

The correct option is C −0.15 m/secLet the velocity of 2nd ball be v m/smA=0.2 kg;vA=0.3 m/s;m2=0.4 kg;v2=vApplying Momentum Conservation:Initial Momentum=Final Momentum⇒mAvA+mBvB=0(final momentum)⇒0.2×0.3+0.4×v=0⇒−0.06/0.4=v⇒v=−0.15 m/s

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