Two spheres carrying charges +6uc and+9uc separated by distance d experience a force of repulsion F.When a charge of -3uc is given to both the sphere and kept at the same distance as before the new force od repulsion is
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Solution
Dear student, the force of repulsion is given by F=kQ1 Q2/r²
=k54/r² Q1=6uc Q2=9uc On addition of -3uc the charges become Q1=3uc Q2=6uc Now force will be =k18/r