wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two spheres each of mass M and radius R2 are connected with a massless rod of length 2 R. The moment of inertia of the system about an axis passing through the centre of one of the spheres and perpendicular to the rod is:
19656_915792ab30a24cebbd7dec4e49c79498.png

A
MR2/10
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
41 MR2/10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
21 MR2/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5 MR1/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A MR2/10
By parallel axis theorem, the moment of inertia of a solid sphere about any parallel axis is
I=I+mx2
I=25M(R2)2+M(2R)2
because the moment of inertia of solid sphere is 25MR2
Total moment of inertia is
2(25M(R2)2)+M(2R)2
=MR25+4MR2=215MR2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Equation of State
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon