Two spherical conductors $A$ and $B$ or radii $2 m m$ and $3 m m$ are separated by a distance of $5 c m$ and are uniformly charged. If the spheres are connected by a conducting wire, then, in equilibrium position, the ratio of the magnitudes of electric fields at the surface of the spheres $A$ and $B$ is :

1 : 4

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4 : 1

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3 : 2

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2 : 3

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Solution

The correct option is C $3 : 2$
The ratio of the electric field is given as,

$\frac{E_{A}}{E_{B}} = \frac{r_{B}}{r_{A}}$

$\frac{E_{A}}{E_{B}} = \frac{3}{2}$

Thus, the ratio of the electric fields at the surface of the surface of the spheres A and B is $3 : 2$ .

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Two spherical conductors A and B or radii 2mm and 3mm are separated by a distance of 5cm and are uniformly charged. If the spheres are connected by a conducting wire, then, in equilibrium position, the ratio of the magnitudes of electric fields at the surface of the spheres A and B is :

The correct option is C 3:2The ratio of the electric field is given as, EAEB=rBrA EAEB=32 Thus, the ratio of the electric fields at the surface of the surface of the spheres A and B is 3:2.

The correct option is C $3 : 2$
The ratio of the electric field is given as,

$\frac{E_{A}}{E_{B}} = \frac{r_{B}}{r_{A}}$

$\frac{E_{A}}{E_{B}} = \frac{3}{2}$

Thus, the ratio of the electric fields at the surface of the surface of the spheres A and B is $3 : 2$ .