Question

Two spherical conductors of capacitance $3.0\mu \text{F}$ and $5.0\mu \text{F}$ are charged to potentials of $300\text{volt}$ and $500\text{volt}$. The two are connected, resulting in redistribution of charges. Then the final potential is (in volt) -

• A. 425.0
• B. 425
• C. 425.00

Answer 1

Answer: (A), (B), (C)

Given,
$C_1=3\mu \text{F};V_1=300\text{volt}$
$C_2=5\mu \text{F};V_2=500\text{volt}$

Since charge stored in the capacitor is given by, $Q=CV$

$\therefore Q_1=900\mu \text{C};Q_2=2500\mu \text{C}$

When the two capacitors are connected together, let the common potential is $V$.

By the conservation of charge,

$900+2500=(3+5)V$

$V=\frac{3400}{8}=425\text{V}$