MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Definition of a Projectile

Two springs A...

Question

Two springs A and B, having force constant KA and KB (KA = 3KB) are stretched by applying equal forces. If energy stored in A is E, then that in B is 1)E/3 2)E 3)3E 4)9E

Open in App

Solution

Suggest Corrections

thumbs-up

3

Similar questions

Q. Two springs A and B having spring constant

K_{A}

K_{B}

K_{A} = 2 K_{B}

) are stretched by applying force of equal magnitude. If energy stored in spring A is

E_{A}

then energy stored in B will be

Q. Two springs have force constants

k_{A}

k_{B}

k_{B} = 2 k_{A}

. The four ends of the springs are stretched by the same force. If energy stored in spring A is

E

, then energy stored in spring B is

Q. Two springs A and B (

k_{A} = 2 k_{B}

) are stretched by applying forces of equal magnitudes at the four ends. If the energy stored in A is E, then in B is (assume equilibrium):

A

B

are stretched by applying forces of equal magnitudes. If the energy stored in

A

is E, then the energy stored in B will be-
(Given relation between spring constants of

A

B

(k_{A} = 2 k_{B})

)

A

B

k_{A} = 2 k_{B}

) are stretched by applying forces of equal magnitudes at the four ends. If the energy stored in

A

E

B

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Basketball

PHYSICS

Watch in App

explore_more_icon

Explore more

Definition of a Projectile

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon