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Elastic Potential Energy

Two springs h...

Question

Two springs have their force constant as $k_{1}$ and $k_{2} (k_{1} > k_{2})$ . When, they are stretched by the same force, then,

A

More work is done in case of first spring

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B

Less work is done in case of first spring

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C

More work is done in case of second spring

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D

Loss work is done in case of second spring

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Solution

The correct options are
B More work is done in case of second spring
D Less work is done in case of first spring
Work done
$W = \frac{F}{2 k}$
Given, $F_{1} = F_{2} = F$
$∴ W \propto \frac{1}{k}$
Given, $k_{1} > k_{2}$
$\Rightarrow W_{2} > W_{1}$
Hence, more work is done is case of second spring.

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