Two super imposing wave have equation y1=2sin2π(10t-0.4x) and Y2=4sin2π (20t-0.8x). What is ratio of iMax:I min.
Open in App
Solution
Two waves superimpose when their frequencies are equal so taking 2 common from equation 2 we get Y2=8sin2π (10t-0.4x). now a1=2 a2=8 imax=(a1+a2)^2=(8+2)^2=100 i min=(a1-a2)^2=(2-8)^2=36 i max/i min=100/36=25:9