Two thin lenses of focal lengths $f_{1} a n d f_{2}$ are in contact and co-axial. the combination is equivalent to single lens of power

f_{1} + f_{2}

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\frac{f_{1} f_{2}}{f_{1} + f_{2}}

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\frac{f_{1} + f_{2}}{2}

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\frac{f_{1} + f_{2}}{f_{1} f_{2}}

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Solution

The correct option is D $\frac{f_{1} + f_{2}}{f_{1} f_{2}}$
The power of the lenses get added when they are kept together.
Thus $P = P_{1} + P_{2}$

$⟹ P = \frac{1}{f_{1}} + \frac{1}{f_{2}} = \frac{f_{1} + f_{2}}{f_{1} f_{2}}$

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Similar questions

f_{1}

f_{2}

If two thin lenses of focal length f₁ and f₂ are held in contact then the focal length of the combination will be

f_{1}

f_{2}

f_{1}

f_{2}

\frac{1}{f} = \frac{1}{f_{1}} + \frac{1}{f_{2}}

∣ ∣ ∣_{1} \times_{2} ∣ ∣ ∣ =_{1} ._{2}

∣ ∣ ∣_{1} +_{2} ∣ ∣ ∣

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