Question

Two toroidal solenoids are wound around the same pipe so that the magnetic field of one passes through the turns of the other. Solenoid $1$ has $700$ turns and solenoid $2$ has $400$ turns. When the current in solenoid $1$ is $6.52A$, the average flux through each turn of solenoid $2$ is $0.0320Wb$. When the current in solenoid $2$ is $2.54A$, what is the average flux through each turn of solenoid $1$?

• A. $7.12\times {10}^{-3}Wb$
• B. $5.12\times {10}^{-7}Wb$
• C. $9.12\times {10}^{-9}Wb$
• D. $7.12\times {10}^{-13}Wb$

Answer 1

The correct option is A $7.12\times {10}^{-3}Wb$

$M=\frac{N_2{\varphi }_2}{i_1}=\frac{\left(400\right)\left(0.032\right)}{6.52}$
$=1.96H$

$M=\frac{N_1{\varphi }_1}{i_2}$
${\varphi }_1=\frac{M{i}_2}{N_1}=\frac{\left(1.96\right)\left(2.54\right)}{700}$
$=7.12\times {10}^{-3}Wb$