Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

58 sec

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50 sec

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48 sec

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56 sec

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None of the above

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Solution

The correct option is C 48 sec
Relative speed=(60+90)
Time = $\frac{(1.10 + 0.9)}{150} = \frac{1}{75} h r 1 h o u r - 3600 s e c 1 / 75 h r - ? ? = 3600 / 75 = 48 s e c$

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Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

The correct option is C 48 secRelative speed=(60+90) Time =(1.10+0.9)150=175hr1hour−3600 sec1/75hr−??=3600/75=48sec

The correct option is C 48 sec
Relative speed=(60+90)
Time = $\frac{(1.10 + 0.9)}{150} = \frac{1}{75} h r 1 h o u r - 3600 s e c 1 / 75 h r - ? ? = 3600 / 75 = 48 s e c$