Two trains are running in opposite directions with the same speed.If the length of each train is 120 meters long and they cross each other in 12 seconds,then the speed of each train is

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Solution

Let the speed of each train be $x$ m/sec.
Relative speed of the train $= 2 x$ m/sec.
So $2 x = \frac{120 + 120}{12}$
$\Rightarrow 2 x = \frac{240}{12}$
$x = \frac{20}{2} = 10$
Speed of each train $= (10 \times \frac{18}{5})$ km/hr $= 36$ km/hr.

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Two trains are running in opposite directions with the same speed.If the length of each train is 120 meters long and they cross each other in 12 seconds,then the speed of each train is

Let the speed of each train be x m/sec.Relative speed of the train =2x m/sec.So 2x=120+12012⇒2x=24012x=202=10Speed of each train =(10×185) km/hr =36 km/hr.

Let the speed of each train be $x$ m/sec.
Relative speed of the train $= 2 x$ m/sec.
So $2 x = \frac{120 + 120}{12}$
$\Rightarrow 2 x = \frac{240}{12}$
$x = \frac{20}{2} = 10$
Speed of each train $= (10 \times \frac{18}{5})$ km/hr $= 36$ km/hr.