CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Two trains , one coming toards and another going away from an observer both at 4 m/s produce a whistle simultaneously of frequency 300 Hz . find the number of beats produced approximately $$ ( V_{sound} =332 m/s) $$


A
5
loader
B
6
loader
C
7
loader
D
12
loader

Solution

The correct option is D 7
$$ Beats = f_1 - f_2$$
here, $$f_1 = f_{whistle} \times \left( \dfrac{V_{sound}}{ V_{sound} - V_{source}} \right)= 300 \times \dfrac{332}{332 - 4} = 303.65 Hz$$

$$f_2 = f_{whistle} \times \left( \dfrac{V_{sound}}{ V_{sound} - V_{source}} \right)= 300 \times \dfrac{332}{332 + 4} = 296.42 Hz$$

$$ Beats = f_1 - f_2= 303.65 - 296.42 = 7.22 Hz \approx 7 Hz$$


Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image