Two tuning forks A and B produce 6 beats/sec when sounded together. When B is slightly loaded with wax, the beats are reduced to 4beats/sec. If the frequency of A is 512Hz, the frequency of B is
A
506 Hz
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B
516 Hz
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C
508 Hz
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D
518 Hz
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Solution
The correct option is B 518 Hz When loaded with wax, frequency of beats is reduced. ⇒ Frequency of B is higher than that of A. ⇒fB−fA=6 ⇒fB=(512+6)=518Hz