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Standard XII

Physics

Wave Equation

Two tuning fo...

Question

Two tuning forks of frequency 250Hz and 256Hz produce beats. If a maximum intensity is observed at t = 0. At what time instant(s), the minimum intensity is observed at the same place?

$\frac{1}{18}$ sec.

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$\frac{1}{4}$ sec.

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$\frac{1}{3}$ sec.

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$\frac{1}{12}$ sec.

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Solution

The correct options are
B
$\frac{1}{4}$ sec.

D
$\frac{1}{12}$ sec.

6 beats per second. So, Time period of oscillations is $T = \frac{1}{6} s$

If maximum is at t = 0, then minima is at $\frac{T}{2} (\frac{1}{12} s), \frac{3 T}{2} (\frac{1}{4} s)$

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Two tuning forks of frequency 250Hz and 256Hz produce beats. If a maximum intensity is observed at t = 0. At what time instant(s), the minimum intensity is observed at the same place?

The correct options are B 14 sec. D 112 sec. 6 beats per second. So, Time period of oscillations is T=16s If maximum is at t = 0, then minima is at T2(112s),3T2(14s)

The correct options are
B
$\frac{1}{4}$ sec.

D
$\frac{1}{12}$ sec.

6 beats per second. So, Time period of oscillations is $T = \frac{1}{6} s$

If maximum is at t = 0, then minima is at $\frac{T}{2} (\frac{1}{12} s), \frac{3 T}{2} (\frac{1}{4} s)$