Two unequal masses of 1kg and 2kg are connected by an inextensible light string passing over a smooth pulley as shown in the figure. A force F=20N is applied on 1kg block. Find the acceleration of either block. (g=10m/s2) in m/s2
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Solution
The given system can be represented as shown
Total downward force on 1kg mass = F+g=20+10=30N
And, on 2kg mass = 2g=20N
Hence, 1kg mass will accelerate downwards
For 1kg mass we have, 30−T=a ........... (1)
For 2kg mass we have, T−20=2a ...........(2)
From (1) & (2) we get 10=3a⇒a=103m/s2