You visited us 1 times! Enjoying our articles? Unlock Full Access!

Resistors in parallel

Two wires of ...

Question

Two wires of resistance $R_{1}$ and $R_{2}$ are joined in parallel. The equivalent resistance of the combination is:

R_{1} R_{2} / (R_{1} + R_{2})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

R_{1} + R_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R_{1} \times R_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R_{1} R_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $R_{1} R_{2} / (R_{1} + R_{2})$
The equivalent resistance of N resistors connected in parallel connection is given by,
$\frac{1}{R_{E q u i v a l e n t}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + . . . + \frac{1}{R_{N}}$
Hence,
$\frac{1}{R_{12}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}$
or,
$R_{12} = \frac{R_{1} R_{2}}{R_{1} + R_{2}}$

Suggest Corrections

Similar questions

R_{1}

R_{2}

R_{p}

R_{1} + R_{2}

R_{1} - R_{2}

\frac{R_{1} R_{2}}{R_{1} + R_{2}}

\frac{R_{1} + R_{2}}{R_{1} R_{2}}

r

V_{1}

V_{2}

r_{1}

r_{2}

\frac{V_{1} r_{2} - V_{2} r_{1}}{r_{1} + r_{2}}, \frac{r_{1} r_{2}}{r_{1} + r_{2}}

When two soap bubbles of radius $r_{1}$ and $r_{2}$ ( $r_{2}$ > $r_{1}$ ) coalesce, the radius of curvature of common surface is

R_{1}

R_{2}

R_{1} > R_{2}

R_{1}

R_{2}

\frac{n}{1}

Join BYJU'S Learning Program