Two wires of same diameter of the same material having the length l and 2l. If the force F is applied on each, the ratio of the work done in the two wires will be

1 : 2

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1 : 4

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2 : 1

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1 : 1

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Solution

The correct option is A
1 : 2

$W = \frac{1}{2} F e a n d e \propto l ∴ W \propto l$ (F is constant)

$∴ \frac{W_{1}}{W_{2}} = \frac{l_{1}}{l_{2}} = \frac{l}{2 l} = \frac{1}{2}$

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Two wires of same diameter of the same material having the length l and 2l. If the force F is applied on each, the ratio of the work done in the two wires will be

The correct option is A 1 : 2 W=12Fe and e∝l∴ W∝l (F is constant) ∴W1W2=l1l2=l2l=12

The correct option is A
1 : 2

$W = \frac{1}{2} F e a n d e \propto l ∴ W \propto l$ (F is constant)

$∴ \frac{W_{1}}{W_{2}} = \frac{l_{1}}{l_{2}} = \frac{l}{2 l} = \frac{1}{2}$