Question

Two years ago,father was three times as old as his son and two years hence,twice his age will be equal to five times that of his son.find their present age

Answer 1

Let the present age as Son $=x$ yrs

Present age of father $=y$ yrs

Two years ago :

Son's age $=(x-2)$ yrs

Father's age $=(y-2)$ yrs

Therefore, $y-2=3(x-2)$

$3x-y=4$ ...(1)

After Two years:

Son's age $=(x+2)$ yrs

Father's age $=(y+2)$ yrs

Therefore, $2(y+2)=5(x+2)$

$5x-2y=-6$ ....(2)

Solving equations 1 & 2, we get

$x=14$ & $y=38$

Hence, present age of Son is 14 yrs and present age of father is 38 yrs.