Two years ago Manohar purchased a machine for ₹ 47,000.If its value falls by 3% every year .What is the value of machine today?
P= Value of machine two years ago= ₹ 47,000
R= -3 p.c.p.a ( since the value is depreciating)
A = Value after two years
=P(1+r100)n
=47,000(1+−3100)2
=47,000(97100)2
=47,000×97100×97100
=44,222.30
The present value of machine = ₹ 44,222.30