CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question


Type of hybridization of complex (E) is:

A
sp3d2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
d2sp3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
sp3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
dsp2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A sp3d2
2Pb(NO3)2(A)Δ2PbO+4NO2(B)+O2Pb(NO3)2(A)+H2SPbS(F)PbS(F)+dil. HNO3Pb(NO3)2+NO(H)+H2O(G)Pb(NO3)2(A)+K2CrO4PbCrO4(I)+2KNO3NO2(B)+NO(H)very low temp.−−−−−−−N2O3(C)N2O3(C)+H2O2HNO2(D)2HNO2(D)+2FeSO4+H2SO4Fe2(SO4)3+2NO+2H2OFeSO4+NO[Fe(H2O)5NO]SO4(E)

In [Fe(H2O)5NO]SO4,Fe is in +1 oxidation state.
26Fe=[Ar]3d64s226Fe1+=[Ar]3d64s1
Since NO is a strong field ligand, it will move 4s electron to the 3d subshell.
26Fe1+=[Ar]3d74s04p04d0
Hence, the compound (E) will form octahedral geometry with sp3d2 hybridization (outer orbital complex).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nomenclature of Compounds Involving Functional Groups
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon