Under constant pressure, the temperature of 3 mol of an ideal monoatomic gas is raised by 15 K. What is the change in average kinetic energy per atom?
0.00194 eV
Since,
(K.E)=32KBT, per molecule,
Change in {K.E} for a change in tempreture will be -
Δ(K.E)=32KBΔT
=(32×1.38×10−23×15)×(6.242×1018) eV
=1.94×10−3eV.