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Dalton's Law of Partial Pressures

under identic...

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under identical conditions of pressure and temperature2L of gaseous mixture (H2 and CH4) effuses through a hole in 5 min whereas 2 litres of a gasX of molecular mass 36 takes 10 minutes to effuses through the same hole. The mole ratio of H2: CH4 in the mixture i

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Q. Under identical conditions of pressure and temperature,

4 L

of gaseous mixture

(H_{2}

C H_{4})

effuses through a hole in

5

4 L

X

ofm molecular mass

36

10

min to effuse through the same hole. The mole ratio of

H_{2} : C H_{4}

in the mixture is:

Q. One litre of a gaseous mixture of two gases effuses in 311 seconds while 2 liters of oxygen takes 20 minutes. The vapour density of the gaseous mixture containing

{C H}_{4}

H_{2}

:

Q. Calculate relative rate of effusion of

S O_{2}

C H_{4}

under given condition:

( i ) Under similar condition of pressure & temperature
( ii ) Through a container containing

S O_{2}

C H_{4}

in 3 : 2 mass ratio
( iii ) If the mixture obtained by effusing out a mixture

(n_{S O_{2}} / n_{C H_{4}} = 8 / 1)

for three effusing steps.

Q. A gaseous mixture of

H e

C H_{4}

gases with mole ratio 2 : 1 respectively is placed in a container and allowed to effuse through a small orifice.

X m l

H e

gas effuses in 5 seconds. The time required to effuse same volume of

C H_{4}

Q. A gaseous mixture of

H e

C H_{4}

gases with mole ratio 2: 1 respectively are placed in a container and allowed to effuse through a small orifice.

X

m l

H e

gas effuses in 5 seconds. The time required to effuse the same volume of

C H_{4}

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