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Question

# Under the same reaction conditions, initial concentration of 1.386 mol dmâˆ’3 of a substance becomes half in 40 seconds and 20 seconds through first order and zero order kinetics respectivley. Ratio (k1k0) of the rate constant for first order (k1) and zero order (k0) of the reaction is:

A
0.5 mol1dm3
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B
1 mol dm3
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C
1.5 mol dm3
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D
2 mol1dm3
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Solution

## The correct option is C 0.5 mol−1dm3t1/2=0.693k1, t1/2=a02k040=0.693k1, 20=1.3862k0=0.693k02040=0.693/k00.693/k1=k1k0k1k0=0.5sec−1moldm−3sec−1=0.5mol−1dm3

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