1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Under the same reaction conditions, initial concentration of 1.386 mol dm−3 of a substance becomes half in 40 s amd 20 s through first order and zero order kinetics respectively. Ratio (k1k0) of the rate constants for first order (k1) and zero order (k0) of the reaction is:

A

0.5 mol1 dm3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

1.0 mol dm3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

1.5 mol dm3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

2.0 mol1 dm3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.5 mol−1 dm3 For first order reaction t1/2=In 2k1=40 s ⋯(i) For zero order reaction t1/2=[A]02k0=20 s ⋯(ii) ⇒Eq.(ii)/(i)=12=[A]02k0×k1In 2 ⇒k1k0=In 2[A]0=0.6931.386=0.5

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Half Life
CHEMISTRY
Watch in App
Explore more
Join BYJU'S Learning Program