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Reactivity Towards Halogens

CH 2= A CH -≡...

Question

$C H_{2} = C H - \equiv C H (A) H C l - -- \to 1 m o l (B)$

The product (B) is:

A

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B

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C

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D

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Solution

The correct option is A
Although double bond is more reactive than triple bond, electrophilic addition of 1 mole of $H C l$ takes place at triple bond because it gives more stable conjugated diene.

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Similar questions

C H_{3} - C H = C H_{2} + H C l \to

the product is:

Q. Match the column

A, B

C

Reactabts $(A)$	Products $(B)$	Name of the reaction $(C)$
$C H_{3} - C H_{3} + C l_{2}$	$C O_{2} + H_{2} O$	Addition reaction
$C_{2} H_{6} + O_{2}$	$C H_{2} = C H_{2}$	Thermal cracking
$_{n} C H_{2} = C H_{2}$	$C H_{2} = C H_{2} + C H_{4}$	Substitution reactions
$C H_{3} - C H_{2} - C H_{3}$	$C H_{3} - C H_{2} C l + H C l$	Polymerisation
$C H \equiv C H + H_{2}$	$[- C H_{2} - C H_{2} -]_{n}$	Combustion

Q. Complete table.

Chemical reaction	Product	$I U P A C$ name of the product
$C H_{2} = C H_{2} + C l_{2}$	........	........
$C H_{2} = C H_{2} + H C l$	..........	.........
$C H_{3} - C h = C H_{2} + H_{2}$	..........	..........
$C H_{3} - C H = C H - C H_{3} + H B r$	...........	........

C H_{2} = C H - C H = C H_{2} + H C l (1 mole) \to Product(s)

Number of chiral atom in kinetically favoured product of the given reaction is:

Q. Predict the product

^{'} C^{'}

obtained in the following reaction of

1

C H_{3} - C H_{2} - C \equiv C H + H C l ⟶ B H I - -------- \to C

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Reactivity Towards Halogens

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