-limsin2 - - sin2 -2 - -2 is equal to

Α→βlimsin^2 α sin^2 β/α^2 β^2 = α→βlimsin(α β) sin (α + β)/(α β)(α+β) = sin 2 β/(2 β) ...

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Standard Limits to Remove Indeterminate Form

α→βlimsin2 α ...

Question

$lim α \to β \frac{{sin}^{2} α - {sin}^{2} β}{α^{2} - β^{2}}$ is equal to

\frac{sin 3 β}{(4 β)}

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\frac{sin 2 β}{(2 β)}

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\frac{sin 8 β}{(7 β)}

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\frac{sin 6 β}{(4 β)}

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Solution

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Similar questions

lim α \to β \frac{{sin}^{2} α - {sin}^{2} β}{α^{2} - β^{2}}

lim α \to β [\frac{{sin}^{2} α - {sin}^{2} β}{α^{2} - β^{2}}]

α

β

x^{2} - 4 \sqrt{2} k x + 2 e^{4 l n k} - 1 = 0

k

α^{2} + β^{2} = 66

α^{2} + β^{2} + α + β

α

β

a x^{2} - b x - c = 0

α^{2} - α β + β^{2}

α, β

x^{2} - x + 1 = 0

\frac{{(α^{2} - α)}^{3} + {(β^{2} - β)}^{3}}{(2 - α) (2 - β)}

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