Question

$\underset{\left(C_3{H}_{7}N{O}_3\right)}{\left(A\right)\alpha -\text{Amino acid}}\underset{HCl}{\overset{MeOH}{\to }}\underset{\left(C_4{H}_{10}N{O}_{3}Cl\right)}{\left(B\right)}\stackrel{PC{l}_5}{\to }\underset{\left(C_4{H}_{9}N{O}_{2}C{l}_2\right)}{\left(C\right)}$

$\underset{\left(C_4{H}_{9}N{O}_{2}C{l}_2\right)}{\left(C\right)}\stackrel{H_3{O}^{+}}{\to }\underset{\left(C_3{H}_{6}N{O}_{2}Cl\right)}{\left(D\right)}\underset{HCl}{\overset{Na-Hg}{\to }}\text{Alanine}$

Compound (C) is :

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Compound A is serine having functional groups $-OH$, $-COOH$ and $-N{H}_2$.