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Byju's Answer
Standard XII
Mathematics
L'Hospital Rule to Remove Indeterminate Form
x→π/ 2 lim ta...
Question
l
i
m
x
→
π
2
t
a
n
2
x
x
−
π
2
Open in App
Solution
lim
x
→
π
/
2
tan
2
x
x
−
π
2
=
Indeterminate form
Applying L'Hospital Rule
lim
x
→
π
2
sec
2
2
x
×
(
2
)
1
−
0
=
sec
2
π
=
1
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0
Similar questions
Q.
l
i
m
x
→
π
/
2
tan
2
x
[
(
2
sin
2
x
+
3
sin
x
+
4
)
1
/
2
−
(
sin
2
x
+
6
sin
x
+
2
)
1
/
2
]
is
1
m
Find
m
Q.
Let
f
(
x
)
=
⎧
⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎨
⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎩
−
2
sin
x
,
−
π
≤
x
≤
−
π
2
a
sin
x
+
b
,
−
π
2
<
x
<
π
2
cos
x
,
π
2
≤
x
≤
π
If
f
(
x
)
is continuous on
[
−
π
,
π
]
, then
Q.
lf
f
(
x
)
=
⎧
⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎨
⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎩
−
x
−
π
2
,
x
≤
−
π
2
−
c
o
s
x
,
−
π
2
<
x
≤
0
x
−
1
,
0
<
x
≤
1
l
n
x
,
x
>
1
then
Q.
Let
g
(
x
)
=
f
(
tan
x
)
+
f
(
cot
x
)
for
x
∈
(
π
2
,
π
)
. If
f
′′
(
x
)
<
0
∀
x
∈
(
π
2
,
π
)
,
then
Q.
The maximum value of
s
i
n
(
x
+
π
6
)
+
c
o
s
(
x
+
π
6
)
in the
interval
(
0
,
π
2
)
is attained at