Uniform rod $A B$ is hinged at end $A$ in horizontal position as shown in the figure. The other end is connected to a block through a massless string as shown. The pulley is smooth and massless. Masses of block and rod is same and is equal to $m$ . Then acceleration of block just after release from this position is

6 g / 13

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g / 4

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3 g / 8

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Solution

The correct option is C $3 g / 8$
$\begin{matrix} a = \frac{m g - T}{m} - - - - - (1) α = \frac{T}{I} = \frac{T \cdot l - m g \cdot \frac{l}{2}}{(m l^{2} / 3)} o r, α = \frac{1}{m l} [3 T - \frac{3 m g}{2}] - - - - (2) a = l α - - - - - (3) S o l v i n g t h e s e t h r e e e q u a t i o n s w e g e t, a = \frac{3 g}{8} \end{matrix}$

Hence,

option $(C)$ is correct answer.

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Uniform rod $A B$ is hinged at end $A$ in horizontal position as shown in the figure. The other end is connected to a block of mass $m$ through a massless string as shown. The pulley is smooth and massless. Mass of block and rod is same and is equal to $m$ . Then find the acceleration of the block just after release.